Finding Coordinates Using Trigonometric Functions A Step By Step Guide

Hey guys! Today, we're diving into the fascinating world of trigonometry, specifically how trigonometric functions like sine, cosine, and tangent relate to coordinates on a circle. We've got a cool problem to tackle that will help us understand this connection deeply. So, buckle up and let's get started!

Understanding Trigonometric Functions

When we talk about trigonometric functions, we're essentially dealing with ratios of sides in a right-angled triangle. But, these functions become even more powerful when we extend them to the unit circle. A unit circle, for those who might need a refresher, is a circle with a radius of 1 centered at the origin (0,0) in a coordinate plane. The magic happens when we consider an angle θ (theta) formed by the positive x-axis and a ray that intersects the unit circle. This intersection point gives us coordinates (x, y), which are intimately linked to our trigonometric functions.

Specifically:

  • Sine (sin θ) is defined as the y-coordinate of the point where the terminal ray of the angle intersects the unit circle.
  • Cosine (cos θ) is the x-coordinate of that same point.
  • Tangent (tan θ) is the ratio of the y-coordinate to the x-coordinate, or sin θ / cos θ.

These definitions are super important because they allow us to connect angles with coordinates, opening up a whole new way to think about trigonometry. The beauty of the unit circle is that it provides a visual and geometric interpretation of trigonometric functions, making them easier to understand and apply. Imagine rotating a point around the circle; as the angle changes, the x and y coordinates dance around, tracing out the cosine and sine waves we often see in graphs. This dynamic relationship is at the heart of many applications of trigonometry in fields like physics, engineering, and computer graphics.

Moreover, the signs of these functions in different quadrants of the coordinate plane are crucial. In the first quadrant (where both x and y are positive), all trigonometric functions are positive. In the second quadrant (where x is negative and y is positive), sine is positive, while cosine and tangent are negative. In the third quadrant (where both x and y are negative), tangent is positive, while sine and cosine are negative. Finally, in the fourth quadrant (where x is positive and y is negative), cosine is positive, while sine and tangent are negative. Remembering these sign conventions is essential for accurately determining the values of trigonometric functions and the coordinates of points on the unit circle. So, let's keep these definitions and the unit circle concept in mind as we dive into our problem.

Problem Statement: Decoding the Coordinates

Okay, so here's the problem we're going to crack today. We're given the values of three trigonometric functions for a specific angle θ:

  • sin θ = -77/85
  • cos θ = 36/85
  • tan θ = -77/36

Our mission, should we choose to accept it (and we do!), is to find the coordinates (x, y) of the point on the terminal ray of this angle. Now, at first glance, this might seem a bit daunting. We have fractions, negative signs, and the mysterious angle θ lurking in the background. But don't worry, guys! We have all the tools we need to solve this. The key here is to remember our definitions of sine, cosine, and tangent in terms of the unit circle.

These values give us a ton of information about the angle θ and where its terminal ray lies. The fact that sin θ is negative tells us that the y-coordinate of the point we're looking for is negative. Similarly, the fact that cos θ is positive tells us that the x-coordinate is positive. Combining these two pieces of information, we know that the terminal ray of the angle must lie in the fourth quadrant of the coordinate plane. This is because the fourth quadrant is the only quadrant where x is positive and y is negative. So, already, we've narrowed down our search significantly. We're not just blindly looking for any point; we know it has to be in a specific region of the plane. This kind of logical deduction is a powerful tool in trigonometry and in mathematics in general. By carefully analyzing the given information, we can often eliminate possibilities and simplify the problem.

Furthermore, the specific values of sin θ and cos θ provide us with the exact ratios we need to determine the coordinates. Remember, sin θ is the y-coordinate divided by the radius of the circle, and cos θ is the x-coordinate divided by the radius. In our case, we can use these ratios to find the x and y coordinates directly, taking into account the fact that we are not necessarily on the unit circle. This will involve a bit of scaling, but the underlying principle remains the same. So, let's move on to the solution and see how we can use these clues to pinpoint the exact coordinates of our point.

Solution: Finding the Coordinates

Alright, let's roll up our sleeves and find those coordinates! We know that sin θ = -77/85 and cos θ = 36/85. Remember, on the unit circle, sin θ corresponds to the y-coordinate and cos θ corresponds to the x-coordinate. However, the problem doesn't explicitly state that we're on the unit circle. So, we need to consider that the point (x, y) might be on a circle with a radius other than 1. The ratio of x and y will be the same, but the actual values might be scaled.

To tackle this, let's think about a right-angled triangle where the opposite side (relative to θ) is 77 units long, the adjacent side is 36 units long, and the hypotenuse is 85 units long. Why 85? Well, notice that 85 appears in the denominators of our sin θ and cos θ values. This suggests that 85 might be related to the radius of the circle on which our point (x, y) lies. This connection is crucial because it allows us to link the given trigonometric ratios with the geometric properties of the circle. By understanding this relationship, we can effectively translate the abstract trigonometric values into concrete spatial coordinates.

Now, let's express x and y in terms of a scaling factor, say r. We can write:

  • x = r * cos θ = r * (36/85)
  • y = r * sin θ = r * (-77/85)

To find the value of r, we can use the Pythagorean theorem, which states that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. In our case, this translates to:

x² + y² = r²

Substituting our expressions for x and y, we get:

(r * (36/85))² + (r * (-77/85))² = r²

r² * (36/85)² + r² * (-77/85)² = r²

Notice that r² appears on both sides of the equation. This is a good sign because it means we can simplify the equation and potentially solve for r. Now, let's factor out r² from the left side:

r² * [(36/85)² + (-77/85)²] = r²

r² * [(1296/7225) + (5929/7225)] = r²

r² * (7225/7225) = r²

r² * 1 = r²

r² = r²

This equation is true for any value of r. However, this doesn't mean that any value of r is valid in our context. We need to consider the original problem and the given information to determine the correct value of r. Since the hypotenuse of our triangle is 85, a reasonable choice for the radius might be 85. This would simplify our calculations and align with the denominators in the given trigonometric ratios. So, let's assume r = 85 and see if it leads to a consistent solution.

If we assume r=1, then we can directly say that the coordinates (x, y) are (36/85, -77/85). This is because on the unit circle, the radius is 1, and the coordinates are simply the cosine and sine values, respectively. So, our solution is beautifully concise and elegant: the coordinates of the point on the terminal ray of angle θ are (36/85, -77/85).

Conclusion: Trigonometry Unveiled

So, there you have it, guys! We successfully decoded the trigonometric functions and found the coordinates (x, y) on the terminal ray of the angle. By understanding the relationship between sine, cosine, tangent, and the unit circle, we were able to tackle this problem head-on. Remember, trigonometry is all about these relationships and how they connect angles with coordinates. Once you grasp this fundamental concept, you can unlock a world of applications in various fields.

This problem beautifully illustrates how trigonometric functions act as a bridge between angles and coordinates. It highlights the power of the unit circle in visualizing and understanding these functions. By using the given values of sine and cosine, we were able to pinpoint the exact location of the point on the terminal ray, demonstrating the practical application of these mathematical concepts. The key takeaway here is that trigonometry is not just about memorizing formulas; it's about understanding the underlying relationships and using them to solve problems. So, keep exploring, keep questioning, and keep unraveling the mysteries of mathematics!

I hope this explanation was helpful and that you enjoyed this trigonometric adventure. Keep practicing, and you'll become a trigonometry master in no time! Until next time, keep those angles sharp and those coordinates precise!